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by riiz
------
[tex]³C₂ = [/tex]
[tex] \sqrt[3]{625 - 125} = [/tex]
jwb yg bener![]()
by riiz
------
[tex]³C₂ = [/tex]
[tex] \sqrt[3]{625 - 125} = [/tex]
jwb yg bener
Penjelasan dengan langkah-langkah:
³C₂
= C ( 3, 2 )
= 3!/2!(3 - 2)!
= 3!/2!(1!)
= (3 × 2!)/(2! × 1!)
*coret 2!
= 3/1
= 3
____________
³√625 - 125
= ³√500
= ³√125 × 4
= 5³√4
